Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 5 - Molecules and Compounds - Exercises - Problems - Page 156: 27

Answer

$2.056 kg$ Fluorine.

Work Step by Step

Using the ratio between the amount of fluorine and magnesium produced from the first sample it's clear that the fluorine produced is roughly 1.56 times more than the amount of magnesium produced. $2.57kg\div1.65 kg = 1.55757$ Therefore, to determine how much fluorine is produced from the second sample, this factor can be multiplied by the amount of magnesium produced which in this case is 1.32 kg. Therefore $1.32*1.55757 = 2.056 kg$
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