Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 4 - Atoms and Elements - Exercises - Problems - Page 124: 97

Answer

85.47 amu

Work Step by Step

We find the atomic mass: Atomic mass = $(\frac{72.17}{100}\times84.9118 amu)+(\frac{27.83}{100}\times86.9092 amu)$ = 85.47 amu
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