Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 2 - Measurement and Problem Solving - Exercises - Cumulative Problems - Page 53: 109

Answer

The mass of the water in pounds is $252074.24 lb$

Work Step by Step

First we must convert the units of $yd^{3}$ into units of $m^{3}$ because we will use the density of water (i.e. 997 kg/m^3) to determine the mass of the water. $ {150 yd^{3}}\times\frac{0.764555 m^{3}}{1 yd^{3}} = 114.683 m^{3}$. Now we can take our unit of volume and multiply it by the density of water; $114.683 m^{3} \times 997 \frac{kg}{m^{3}} = 114338.951 kg$. Lastly we must convert the units of kg into lbs because the question asks for the mass in pounds; $114338.951 kg\times2.205 = 252074.24 lb$
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