Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 19 - Biochemistry - Exercises - Cumulative Problems - Page 735: 87

Answer

see solution

Work Step by Step

It is given that insulin is 51 amino acids long. Each amino acid is encoded by a single codon that comprises 3 nucleotides. So, total $51 X 3 = 153$ nucleotides would be required to encode insulin. In general, most of the proteins are encoded as pre-proteins which are processed to form an active protein. So, generally, the gene DNA sequence is much larger than the corresponding final protein sequence.
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