Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 17 - Radioactivity and Nuclear Chemistry - Exercises - Problems - Page 638: 74

Answer

$2.11\times10^{9}\,years$

Work Step by Step

$\frac{1}{8}=\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}$ Three half-lives are needed for the amount of sample to reach one-eighth of its initial amount. That is, $t=3\times703\,million\,years=2.11\times10^{9}\,y$
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