Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 17 - Radioactivity and Nuclear Chemistry - Exercises - Problems - Page 638: 62

Answer

Nuclear equation is as follows for each nuclides:

Work Step by Step

When a beta ray is emitted from the nucleus of a radioactive element, atomic number of that element is increased by 1 unit and mass number does not change. (It is because when a beta ray is emitted from the nucleus, a neutron is converted to a proton and an electron. The formed electron is emitted from the nucleus in the form of beta and atomic number is increased by 1 unit because of that proton formation). So, the daughter nuclide will have atomic number greater than 1 but mass number will be same with parent nuclide. Beta ray is represented as symbol 'e' with -1 on left subscript and 0 on left superscript. Now, let's write the nuclear equation. Pb-211 is converted to Bi-211 after beta decay and beta is emitted in the form of electron from the nucleus. Similarly, Tl-207 is converted to Pb-207 after beta decay. Th-234 is converted to Pa-234. Pa-234 is converted to U-234 after beta emission. When writing nuclear equation, all the elements are represented in symbol (Process to write nuclide in the form of symbol: Write chemical symbol of that element, write atomic number on the left subscript position and mass number on the left superscript position). After writing the nuclear equation, the total mass number (sum of mass number of each nuclide on the left side) on the left side will be equal to the total mass number on the right side (sum of mass number of each nuclide on the right side). Similarly, total atomic number on the left side will be equal to the total atomic number on the right side. General form of nuclear equation is as follows when beta decay is occurred on an element:
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