Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 17 - Radioactivity and Nuclear Chemistry - Exercises - Cumulative Problems - Page 640: 96

Answer

$\frac{1}{18}$th of her total exposure is due to on-the-job exposure.

Work Step by Step

Total exposure = 0.36 rem Radiation due to job = 0.020 rem Hence, Fraction exposure due to on-the-job exposure = $\frac{0.020}{0.36}$ = $\frac{1}{18}$
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