Answer
The equilibrium constant value for this reaction is equal to $17.9$
Work Step by Step
1. Write the equilibrium constant expression:
$K_{eq} = \frac{[Products]}{[Reactants]} = \frac{[CO_2][H_2]}{[CO][H_2O]}$
2. Use the given values to find the $K_{eq}$ value:
$K_{eq} = \frac{0.175 \times 0.0274}{0.0233 \times 0.0115} = 17.9$
