Chapter 15 - Chemical Equilibrium - Exercises - Problems - Page 566: 51

The equilibrium constant for this reaction at that temperature is equal to $3.94 \times 10^{-2}$

1. Write the equilibrium constant expression: $K_{eq} = \frac{[Products]}{[Reactants]} = \frac{[CO][Cl_2]}{[COCl_2]}$ 2. Use the given concentrations to find the $K_{eq}$ value: $K_{eq} = \frac{0.105 \times 0.0844}{0.225} = 3.94 \times 10^{-2}$