Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 14 - Acids and Bases - Exercises - Problems - Page 523: 75

Answer

(a) $[OH^-] = 1.8 \times 10^{- 10}M$ (b) $[OH^-] = 3.4 \times 10^{- 2}M$ (c) $[OH^-] = 3.2 \times 10^{- 13}M$ (d) $[OH^-] = 1.8 \times 10^{- 6}M$

Work Step by Step

1. Calculate the hydroxide ion concentration: pH + pOH = 14 4.25 + pOH = 14 pOH = 9.75 $[OH^-] = 10^{-pOH}$ $[OH^-] = 10^{- 9.75}$ $[OH^-] = 1.8 \times 10^{- 10}M$ 2. Calculate the hydroxide ion concentration: pH + pOH = 14 12.53 + pOH = 14 pOH = 1.47 $[OH^-] = 10^{-pOH}$ $[OH^-] = 10^{- 1.47}$ $[OH^-] = 3.4 \times 10^{- 2}M$ 3. Calculate the hydroxide ion concentration: pH + pOH = 14 1.5 + pOH = 14 pOH = 12.5 $[OH^-] = 10^{-pOH}$ $[OH^-] = 10^{- 12.5}$ $[OH^-] = 3.2 \times 10^{- 13}M$ 4. Calculate the hydroxide ion concentration: pH + pOH = 14 8.25 + pOH = 14 pOH = 5.75 $[OH^-] = 10^{-pOH}$ $[OH^-] = 10^{- 5.75}$ $[OH^-] = 1.8 \times 10^{- 6}M$
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