Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 14 - Acids and Bases - Exercises - Problems - Page 522: 60

Answer

a. KOH is a strong base and dissociates completely. Therefore [K+] = [OH-]. b. $NH_{3}$ is a weak base and dissociates partially. Therefore [OH-] < [$NH_{3}$] c. $Ba(OH)_{2}$ is a strong base and dissociates completely. Therefore [K+] = [OH-]. d. $C_{5}H_{5}N$ is a weak base and dissociates partially. Therefore [OH-] < [ $C_{5}H_{5}N$].

Work Step by Step

a. KOH is a strong base and dissociates completely. Therefore [K+] = [OH-]. b. $NH_{3}$ is a weak base and dissociates partially. Therefore [OH-] < [$NH_{3}$] c. $Ba(OH)_{2}$ is a strong base and dissociates completely. Therefore [K+] = [OH-]. d. $C_{5}H_{5}N$ is a weak base and dissociates partially. Therefore [OH-] < [ $C_{5}H_{5}N$].
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