Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 13 - Solutions - Exercises - Problems - Page 481: 66

Answer

(a) 0.34 moles (b) 1.789 moles (c) 0.011352 moles

Work Step by Step

Molarity = (weight/molecular weight)(1000/V in mL) Molarity = Number of moles / Volume in L Number of moles = Molarity x Volume in L (a) 3.4 L of a 0.100 M sucrose solution Number of moles = 3.4 X 0.1 = 0.34 moles (b) 0.952 L of a 1.88 M sucrose solution Number of moles = 0.952 X 1.88 = 1.789 moles (c) 21.5 mL of a 0.528 M sucrose solution Number of moles = 0.0215 X 0.528 = 0.011352 moles
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