Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 13 - Solutions - Exercises - Problems - Page 481: 62

Answer

(a) 0.498 M (b) 0.391 M (c) 0.00205 M

Work Step by Step

Recall: Molarity= $\frac{\text{moles solute}}{\text{litres solution}}$ (a) Molarity= $\frac{\frac{33.2\,g}{74.5513\,g/mol}}{0.895\,L}=0.498\,M$ (b) Molarity= $\frac{\frac{61.3\,g}{46.07\,g/mol}}{3.4\,L}=0.391\,M$ (c) Molarity= $\frac{\frac{38.2\times10^{-3}\,g}{166\,g/mol}}{112\times10^{-3}\,L}=0.00205\,M$
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