Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 13 - Solutions - Exercises - Problems - Page 481: 61

Answer

(a) 0.149 M (b) 0.461 M (c) 0.0300 M

Work Step by Step

Recall: Molarity= $\frac{\text{moles solute}}{\text{litres solution}}$ (a) Molarity= $\frac{\frac{22.6\,g}{342.3\,g/mol}}{0.442\,L}=0.149\,M$ (b) Molarity= $\frac{\frac{42.6\,g}{58.44\,g/mol}}{1.58\,L}=0.461\,M$ (c) Molarity= $\frac{\frac{315\times10^{-3}\,g}{180.156\,g/mol}}{58.2\times10^{-3}\,L}=0.0300\,M$
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