Answer
38.3 g
Work Step by Step
Given
Mass of water = 55.8 g H2O.
The amount of heat produced by water is calculated using:
q= mC$\Delta t$.
here m= 55.8g
C= 4.184 J/g
$\Delta t$= (0 C-55C)= -55 C
q= mC$\Delta t$ = (55.8 g)x( 4.184 J/g)x(-55C)
q= -12.8 kJ
The amount of heat required for melting 1 mol of ice =6.02 kJ.
So, with -12.8 kJ
= -12.8 kJx( 1mol/ 6.02 kJ)x( 18.02 g/ 1 mol)= 38.3 g
So with -12.8 kJ , we can melt 38.3 g of ice.
