Answer
a) $59.1 L$
b) $30.03 L$
c) $72.07 L$
d) $0.125 L$
Work Step by Step
At Standard Temperature and Pressure (STP) which is 0∘C and 1 atm of pressure, the volume occupied by any gas is 22.4 L. So to find how many liters a gas occupies we can simply multiply the moles of the gas by 22.4 L.
However, we must convert the grams of gas into moles by using its molar mass;
a) $73.9 g N_{2}\times\frac{1 mol N_{2}}{28.02 g/mol} = 2.637 mols$
b) $42.9 g O_{2}\times\frac{1 mol O_{2}}{32.00 g/mol} = 1.341 mols$
c) $148 g NO_{2}\times\frac{1 mol NO_{2}}{46.00 g/mol} = 3.21739 mols$
d) $0.245 g CO_{2}\times\frac{1 mol CO_{2}}{44.01 g/mol} = 5.5669\times10^{-3} mols$
Now we can use the moles of gas to find the volume as shown below;
a) $2.637 mols N_{2}O×22.4= 59.1 L$
b) $1.341 mols O_{2}×22.4= 30.03L$
c) $3.21739 mols NO_{2}×22.4= 72.07 L$
d) $5.5669\times10^{-3} mols CO_{2}×22.4=0.125 L$
