Answer
Naming each ionic compound:
a. $NaF$ - sodium fluoride.
b. $MgO$ - magnesium oxide.
c. $SrBr_{2}$ - strontium bromide.
d. $Li_{2}O$ - lithium oxide.
e. $TiO_{2}$ - titanium oxide.
f. $AlCl_{3}$ - aluminium chloride.
Work Step by Step
a. $NaF$
The cation is sodium and the anion is fluoride (derived from Fluorine); thus, the name is sodium fluoride.
b. $MgO$
The cation is magnesium and the anion is oxide (derived from oxygen); thus, the name is magnesium oxide.
c. $SrBr_{2}$
The cation is strontium and the anion is bromide (derived from bromium); thus, the name is strontium bromide.
d. $Li_{2}O$
The cation is lithium and the anion is oxide (derived from oxygen); thus, the lithium oxide.
e. $TiO_{2}$
The cation is titanium and the anion is oxide (derived from oxygen); thus, the name is titanium oxide.
f. $AlCl_{3}$
The cation is aluminum and the anion is chloride (derived from chlorine); thus, the name is aluminum chloride.
