Answer
Please see the work below.
Work Step by Step
The anion $S^{-2}$ will have a larger radius than $S$. The reason behind this is that anion has more valence electrons which increases the electron-electron repulsion.
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 9 - Ionic and Covalent Bonding - Exercises - Page 345: 9.5
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