Answer
Please see the work below.
Work Step by Step
We know that the electronic configuration of lead $Pb$ is given as [Xe] $4f^{15} 5d^{10} 6s^2 6p^2$.
The electronic configuration of lead ion $Pb^{+2}$ is given as $4f^{14} 5d^{10} 6s^2$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 9 - Ionic and Covalent Bonding - Exercises - Page 343: 9.3
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