Answer
$1.120\times 10^{-27}J$
Work Step by Step
We know that
$E=h\nu$
We plug in the known values to obtain:
$E=6.63\times 10^{-34}\times 1.69\times 10^6=1.120\times 10^{-27}J$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 7 - Quantam Theory of the Atom - Questions and Problems - Page 297: 7.98
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