Answer
$3.585\times 10^{-19}J$
Work Step by Step
We know that
$\nu=\frac{c}{\lambda}$
We plug in the known values to obtain:
$\nu=\frac{2.998\times 10^8}{5.54\times 10^{-7}}=\frac{5.411\times 10^{14}}{s}$
We know also know that
$E=h\nu$
$E=6.626\times 10^{-34}\times (5.411\times 10^{14})=3.585\times 10^{-19}J$