Answer
Please see the work below.
Work Step by Step
We know that
$-369KJ\times \frac{1mol\space C_3H_8}{-2043KJ}\times \frac{44.06gC_3H_8}{1mol\space C_3H_8}=7.957gC_3H_8$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 6 - Thermochemistry - Questions and Problems - Page 262: 6.67
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