General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 4 - Chemical Reactions - Questions and Problems - Page 175: 4.117

Answer

Please see the work below.

Work Step by Step

We know that $0.2122g \space TH\times \frac{1mol\space TH}{331.28g\space TH}\times \frac{504.83g\space TI_2SO_4}{1mol\space TI_2SO_4}=0.16168g\space TI_2SO_4$ Thus $Ti_2SO_4=\frac{0.16168}{0.7590}\times 100\%=21.30\%$
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