Answer
$325.3mL$
Work Step by Step
We know that
$82.0g\space NaHCO_3\times \frac{1mol\space NaHCO_3}{84.01g\space NaHCO_3}\times \frac{1mol\space H_2SO_4}{2mol\space NaHCO_3}\times \frac{1L\space sol}{0.150mol\space H_2SO_4}=0.3253L=325.3mL$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.