Answer
$35.751mL$
Work Step by Step
We know that
$0.0353\space g \space KOH\times \frac{1\space mol\space KOH}{56.10g\space KOH}\times \frac{1 \space L \space solution}{0.0176\space mol \space KOH}=0.035751 L=35.751mL$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 4 - Chemical Reactions - Questions and Problems - Page 172: 4.73
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