General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 4 - Chemical Reactions - Exercises - Page 158: 4.11

Answer

Please see the work below.

Work Step by Step

We know that $0.0958g\space NaCl \times \frac{1\space mol\space NaCl}{58.44g}\times\frac{1\space L \space solution}{0.163\space mol\space NaCl}\times \frac{1000\space mL}{1 L}=10.05\space mL\space NaCl$
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