General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 3 - Calculations with Chemical Formulas and Equations - Questions and Problems: 3.126

Answer

31%

Work Step by Step

6.61*10$^5$ mg = 661 g of the compound Molar mass of the compound = $\frac{661 g}{2.21 mol}$ = 2.99 10$^{2}$ g/mol molar mass of lead (Pb) = 207.2g/mol molar mass of compound - molar mass of lead = molr mass of nitrites = 299- 207.2 = 91.895g $\frac{1.895 g/mol}{ 391g/mol} * 100$%$ = $$30.7$%$ \approx 31%$
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