General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 3 - Calculations with Chemical Formulas and Equations - Questions and Problems - Page 124: 3.121

Answer

Please see the work below.

Work Step by Step

We know that $8.5g\space NH_3\times \frac{1 mol\space NH_3}{17.034g\space NH_3}\times \frac{4 mol\space NO}{4 \space mol\space NH_3}\times \frac{30.01g\space NO}{1\space mol \space NO}=14.97g\space NO$
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