General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 21 - Chemistry of the Main-Group Elements - Questions and Problems - Page 933: 21.177

Answer

$5.325g Al$

Work Step by Step

We can find the mass of $NaCl$ as $10.00g\space NaHCO_3\times\frac{1mol\space NaHCO_3}{84.00g\space NaHCO_3}\times\frac{1 mol\space Nacl}{1 mol\space NaHCO_3}\times \frac{58.44g \space NaCl}{1 mol\space NaCl}=5.325g Al$
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