Answer
Please see the work below.
Work Step by Step
We can find the mass of $Fe$ as
$2\times 10^3gH_2\times \frac{1mol \space H_2}{2.016g\space H_2}\times \frac{2 mol Fe}{3 mol H_2}\times \frac{55.85g\space Fe}{1 mol \space Fe}=3.693\times 10^4\space Fe=36.93Kg \space Fe$
