Answer
Please see the work below.
Work Step by Step
We can separate $MgCl_2$ by adding $OH^{-}$ ion, precipitating $Mg(OH)_2$ while leaving $NaCl$ solution as it is soluble. We filter the solution and separate $Mg(OH)_2$ .
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 21 - Chemistry of the Main-Group Elements - Questions and Problems - Page 930: 21.100
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