General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 2 - Atoms, Molecules, and Ions - Questions and Problems - Page 82: 2.55

Answer

24.62 amu is the atomic mass of hypothetical element X.

Work Step by Step

Strategy: The atomic mass of the element is found by multiplying each isotopic mass by its abundance fraction, and then add all of them. The picture of the report with isotopes X-23 and X-25, will help us to find abundance fraction for each isotope. We are given isotopic mass of each isotopes: X- 23 with 23.02 amu and x-25 with 25.147 amu. We can find the abundance fraction of isotopes. we count in the picture that there are 5 brown colored atoms of isotope X - 23. There are 15 green colored atoms of isotope X - 25. In total there are 20 isotopes of element X. So we can calculate: the abundance fraction of isotope X - 23: $\frac{5}{20}$ = $\frac{1}{4}$ = 0.250 the abundance fraction of isotope X - 25: $\frac{15}{20}$ = $\frac{3}{4}$ = 0.750 Now we can find the atomic mass by multiplying each isotopic mass by its abundance fraction 23.02 amu x 0.250 = 5.7550 amu 25.147 amu x 0.750 = 18.8603 amu ____________________________ Sum: 24.6153 amu So the atomic mass of element X would be 24.6153 amu or 24.62 amu. To check our answer we see that this number is near the mass of isotope X-25 ( with 25.147 amu) that has the greatest abundance of 0.750.
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