Answer
Please see the work below.
Work Step by Step
As $E^{\circ}$ is less negative so $Fe^{+3}$ is reduced at the cathode and is written on the right, $Zn(s)$ is oxidized at the anode and is written first. The notation is given as
$Zn(s)\vert Zn^{+2}(0.20M)\vert \space \vert Fe^{+3}(0.30M)\vert \space \vert Fe(s)\vert $
