Answer
Please see the work below.
Work Step by Step
As $E^{\circ}$ is less negative so $H^{+}$ is reduced at the cathode and is written on the right, $Ni$ is oxidized at the anode and is written first. The notation is given as
$Ni(s)\vert Ni^{+2}(1M)\vert \space \vert H^{+}(1M)\vert \space \vert H_2(g)\vert Pt$
