Answer
Please see the work below.
Work Step by Step
We make the conversion as
$1.054\times 10^3\times \frac{1 \space mol }{ 96.485C}\times \frac{1 \space mol O_2\space }{4 mol O_2}\times \frac{32.00g\space O_2}{1\space mol \space O_2}=0.08666gO_2$
