Answer
Please see the work below.
Work Step by Step
We know that
$\Delta H=1.34 mol\times \frac{26.7Kj}{1 mol}=3.5778\times 10^4J$
Now $\Delta S=\frac{\Delta H}{T}$
We plug in the known values to obtain:
$\Delta S=\frac{3.5778\times 10^{4}}{35.6+273}=115.93\frac{J}{mol.K}$