Answer
Please see the work below.
Work Step by Step
We know that when a small amount of $NaOH$ is added to a solution of $Al_2(SO_4)_3$, we obtain a precipitate of $Al(OH)_3$. By adding further $NaOH$, we obtain $Al(OH)_4^-$.
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 17 - Solubility and Complex-Ion Equilibria - Questions and Problems - Page 733: 17.8
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