General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 15 - Acids and Bases - Questions and Problems - Page 662: 15.132

Answer

Please see the work below.

Work Step by Step

We know that $10.0g BF_3\times \frac{1 mol \space BF_3}{67.81\space g\space BF_3}\times \frac{1\space mol \space BF_3: OR_2}{1 mol\space BF_3}\times \frac{141.93g BF_3:OR_2}{1 \space mol \space BF_3:OR_2}=20.93gBF_3:\space OR_2$
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