Answer
Please see the work below.
Work Step by Step
We know that
$1.00g HA\times \frac{1 mol \space HA}{65.994\space g\space HA}\times \frac{1\space mol \space NaOH}{1 mol\space HA}\times \frac{40.00g NaOH}{1 \space mol \space NaOH}=0.606g\space NaOH$