Answer
Please see the work below.
Work Step by Step
We know that
$K_c=\frac{[CH_3OH]}{[CO][H_2]^2}$
We plug in the known values to obtain:
$K_c=\frac{0.015}{(0.096)(0.191)^2}=4.28$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 14 - Chemical Equilibrium - Questions and Problems - Page 629: 14.83
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