Answer
Please see the work below.
Work Step by Step
We know that
$Q=\frac{[CH_3OH]}{[CO][H_2]^2}$
We plug in the known values to obtain:
$Q=\frac{0.020}{(0.010)(0.010)^2}=20.0>10.5$ hence the reaction goes to the left.
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 14 - Chemical Equilibrium - Questions and Problems - Page 627: 14.63
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