Answer
Please see the work below.
Work Step by Step
We know that
$K_c=\frac{K_p}{(RT)^{\Delta n}}$
We plug in the known values to obtain:
$K_c=\frac{7.55\times 10^{-2}}{(0.0821\times 1115)^{\frac{1}{2}}}=7.891\times 10^{-3}$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 14 - Chemical Equilibrium - Questions and Problems - Page 627: 14.54
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