General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 14 - Chemical Equilibrium - Questions and Problems - Page 626: 14.46

Answer

Please see the work below.

Work Step by Step

We know that $K_c=\frac{[product]^{coefficient }}{[reactant]^{coefficient }}$ $\implies K_c=\frac{[CH_3OH]}{[CO][H_2]^2}$ We plug in the known values to obtain: $K_c=\frac{(0.02086)}{0.07913(0.1582)^2}=10.53$
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