General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 13 - Rates of Reaction - Questions and Problems - Page 585: 13.88

Answer

Please see the work below.

Work Step by Step

We know that a. Only $Cs_2$ occurs on the left side of the equation hence the rate law is $Rate=k[Cs_2]$ b. Both $CH_3Br$ and $OH^-$ occur on the left side of the equation hence form the rate law $Rate=k[CH_3Br][OH^-]$
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