General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 12 - Solutions - Questions and Problems - Page 532: 12.123

Answer

Please see the work below.

Work Step by Step

We know that $S_2=S_1\times \frac{P_2}{P_1}$ We plug in the known values to obtain: $S_2=15.6\frac{g}{L}\times \frac{24.6atm}{2.14atm}=179.3\frac{g}{L}$ Thus by increasing the temperature of the liquid the solubility will decrease.
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