General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 11 - States of Matter; Liquids and Solids - Questions and Problems - Page 482: 11.93

Answer

Please see the work below.

Work Step by Step

We know that $V=\frac{4\pi r^3}{3}$ This simplifies to: $r=(\frac{3V}{4\pi})^{\frac{1}{3}}$ We plug in the known values to obtain: $r=(\frac{3(1.719\times 10^{-23})}{4\pi})^{\frac{1}{3}}=1.601\times 10^{-8}cm$ The conversion of units is made as follows $1.601\times 10^{-8}cm\times \frac{1\times 10^{10}pm}{1cm}=1.60\times 10^2cm$
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