General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 1 - Chemistry and Measurement - Questions and Problems - Page 33: 1.40

Answer

160.7g of bromine is needed to react with 18.1 g of aluminum.

Work Step by Step

1- Step one: Apply the law of conservation of mass for the chemical reaction: m (of aluminum) + m (of bromine) = m (of aluminum bromide) 2- Step two: Replace the mass of aluminum, and mass of aluminum bromide: 27.0 g + m (of bromine) =266.7 g m (of bromine) = 266.7 g – 27.0 g m (of bromine) = 239.7 g 3- Step three: using the law of conservation of mass we found that 27 g of aluminum would react with 239.7 g of bromine. Than what would be the mass of bromine that would be needed to react with 18.1 g aluminum? Applying the knowledge of law of conservation of mass, we can write: 27.0 g aluminum react with 239.7 g bromine 18.1 g aluminum react with unknown mass of bromine 4 – Step four: find the mass of bromine using the mathematical rule of three : Unknown mass of bromine = (18.1 g x 239.7 g) / 27.0 g Unknown mass of bromine = 4338.6 g2 / 27.0 g We find that the mass of bromine is 160.7 g.
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