Chemistry: The Molecular Nature of Matter and Change 7th Edition

Published by McGraw-Hill Education
ISBN 10: 007351117X
ISBN 13: 978-0-07351-117-7

Chapter 7 - Problems: 7.22

Answer

See explanation below.

Work Step by Step

1 Part (A) : The Bohr Model is based on systems having a single electron. No of electrons in H atom = 1 No of electrons in Be(3+) atom = 1 Hence, Bohr model can accurately predict the spectra of these atoms. 2 Part (B) : The energy of an atom in Bohr orbit is given by, E = (-z²)(2.18 x 10^-18 J) / n² For Hydrogen, Z = 1 E for Hydrogen = (-(1²))(2.18 x 10^-18 J) / n² = -(2.18 x 10^-18 J) / n² And, for Berillium, Z = 4 E for Berillium, (-(4²))(2.18 x 10^-18 J) / n² = - 16 x (2.18 x 10^-18 J) / n² Thus, E for Be is 16 times that for H. This means that the patterns will be similar, but will be at at different Wavelengths.
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