Answer
$295^{\circ}C$
Work Step by Step
$q=mc(T_{2}-T_{1})$
$\implies T_{2}=\frac{q}{mc}+T_{1}$
$=\frac{75.0\times1000\,J}{295\,g\times0.900\,J/g\cdot\,^{\circ}C}+13.00^{\circ}C$
$=295^{\circ}C$
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