Chemistry: The Molecular Nature of Matter and Change 7th Edition

Published by McGraw-Hill Education
ISBN 10: 007351117X
ISBN 13: 978-0-07351-117-7

Chapter 12 - Problems: 12.124

Answer

0.0484 g

Work Step by Step

vapor pressure of water at 22 Celsius = 19.8 mm Calculate moles of H2O in 5.0 liters PV= nRT , where n =moles of H2O vapor 19.8 mm x 1 atm/760mm(5 liters) = n(0.082 liter-atm/mol K)(273 + 22) n = 0.00538 moles of H2O vapor Volume reduced to 2.5 liters, then the moles of H2O vapor would 19.8 mm/760 mm(2.5 liters)= n(0.082)295 n = 0.00269 moles moles of H2O that condensed = 0.00538 – 0.00269 = 0.00269 grams of H2O = 0.00269 moles x 18.0 g H2O/mole H2O = 0.0484 g
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